(x-(1/2))^2=-(17/4)

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Solution for (x-(1/2))^2=-(17/4) equation: 


x in (-oo:+oo)

(x-(1/2))^2 = -(17/4) // + 17/4

(x-(1/2))^2+17/4 = 0

(x-1/2)^2+17/4 = 0

(4*(x-1/2)^2)/4+17/4 = 0

4*(x-1/2)^2+17 = 0

4*x^2-4*x+18 = 0

4*x^2-4*x+18 = 0

2*(2*x^2-2*x+9) = 0

2*x^2-2*x+9 = 0

DELTA = (-2)^2-(2*4*9)

DELTA = -68

DELTA < 0

2 = 0

2/4 = 0

2/4 = 0 // * 4

2 = 0

x belongs to the empty set

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